Answer:
0.03719 lbs/in³
Explanation:
Specific weight is given by multiplying the density of an object to the acceleration due to gravity.
[tex]\gamma =\rho g\\\Rightarrow \rho=\frac{gamma}{g}\\\Rightarrow \rho=\frac{10.1\times 10^3}{9.81}\\\Rightarrow \rho=1029.562\ kg/m^3[/tex]
[tex]1\ kg=2.20462\ lb[/tex]
[tex]1\ m=39.3701\ in[/tex]
[tex]\\\Rightarrow 1029.562\ kg/m^3=\frac{1029.562\times 2.20462}{39.3701^3}=0.03719\ lbs/in^3[/tex]
So,
[tex]10.1\ kN/m^3=0.03719\ lbs/in^3[/tex]
