Answer:
[tex]e^x \neq 0[/tex]
Step-by-step explanation:
We will prove this with the help of a contradiction:
Let as assume that [tex]e^x = 0[/tex]
Multiplying both sides by [tex]e^{-x}[/tex]
[tex]e^x\times e^{-x} = 0\times e^{-x}\\e^0 = 0\\1 = 0[/tex]
which is not possible.
Hence, our assumption was wrong which led us to a contradiction.
Thus,
[tex]e^x \neq 0[/tex]
