Answer:
1449.02g
Explanation:
First confirming that the equations are balance, this shows that the mole ratio of NaCl to Na₂CO₃ is 1 : 1
Therefore, given 800g of NaCl which has 23 + 35.5 = 58.5g/mol
No of Mole required will be 800 / 58.5 = 13.67mol
The mass for Na₂CO₃ that has 23*2 + 12 + 16*3 = 106g/mol to be obtained will be 106 * 13.67 = 1449.02g
