Answer:
[tex]\frac{a}{a-1}[/tex]
Step-by-step explanation:
[tex]\frac{a^{2}+4a}{a^{2}+3a-4}[/tex]
factor out the common term (a) in a²+4a:
[tex]\frac{a(a+4)}{a^{2}+3a-4}[/tex]
factor a²+3a-4:
[tex]\frac{a(a+4)}{(a-1)(a+4)}[/tex]
cancel the (a+4):
[tex]\frac{a}{a-1}[/tex]
