mdtrofort
mdtrofort mdtrofort
  • 19-05-2016
  • Chemistry
contestada

How many grams of NH3 can be produced from 4.54 mol of N2 and excess H2?

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InverseOperator
InverseOperator InverseOperator
  • 19-05-2016
First we make a Balanced Chemical Equation:

[tex]N_{2} + 3H_{2} = 2NH_{3} [/tex]


Now we can solve using the Mole Ratio:

4.54 mol N2 × 2 / 1 × 17.04 g/mol NH3 
= 154.72 g

If you need further clarification, feel free to comment. 
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