Answer:
[tex]-0.5[/tex] and [tex]2.5[/tex]
Step-by-step explanation:
[tex]x_{1,2} = \dfrac{\dfrac{-b}{2} \pm \sqrt{\dfrac{b^2}{4}-ac}}{a}= \dfrac{\dfrac{8}{2} \pm \sqrt{\dfrac{64}{4}+\times4\times5}}{4}=\dfrac{4 \pm \sqrt{16+20}}{4}=\dfrac{4\pm6}{4}\\=> x_1 = \dfrac{4+6}{4} = \dfrac{10}{4}=2.5\\=> x_2 = \dfrac{4-6}{4}= \dfrac{-2}{4} = -0.5[/tex]
