Answer:
[tex]4\sqrt{3}[/tex]
Step-by-step explanation:
[tex]-2i\sqrt{-12} \\=-2i\sqrt{(-1)(3)(2^{2})} \\=-2i\sqrt{-1} \sqrt{3} \sqrt{2^{2}} \\=-2i*i*2\sqrt{3} \\=4\sqrt{3}[/tex]
;
If you dont know how "i" works:
[tex]\sqrt{-1} =i\\[/tex]
[tex]i^{2}=-1[/tex]
