Answer:
Explanation:
Energy E is conserved:
[tex]E=\frac{1}{2}mv^2+mgh[/tex]
If v₀ = 22m/s, h₀=0m and h₁=25m:
[tex]E=\frac{1}{2}mv_0^2=\frac{1}{2}mv_1^2+mgh_1[/tex]
Solving for v₁:
[tex]v_1=\sqrt{v_0^2-2gh_1}[/tex]
There is no real solution, because the stone never reaches 25m.
