Answer:
2i[tex]\sqrt{6}[/tex]
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] and
[tex]\sqrt{-1}[/tex] = i
Given
[tex]\sqrt{-24}[/tex]
= [tex]\sqrt{4(6)(-1)}[/tex]
= [tex]\sqrt{4}[/tex] × [tex]\sqrt{6}[/tex] × [tex]\sqrt{-1}[/tex]
= 2 × [tex]\sqrt{6}[/tex] × i
= 2i[tex]\sqrt{6}[/tex]
