Respuesta :
Answer:
Density of the unknown liquid = 1.82537 g/mL.
Explanation:
Given:
- Mass of the empty container, m = 17.322 g.
- Mass of the container with the water at 25°C = 28.699 g.
- Mass of the container with the unknown liquid = 38.028 g.
- Density of the water, [tex]\rm \rho=0.997048\ g/mL.[/tex]
Assumptions:
- Mass of the water at 25°C that fills the container = [tex]\rm m_w[/tex]
- Mass of the unknown liquid that fills the container = [tex]\rm m_l[/tex]
Therefore,
[tex]\rm m+m_w = 28.699\ g\\17.322\ g+m_w = 28.699\ g\\m_w = 28.699-17.322=11.377\ g.\\\\\rho = \dfrac{m_w}{Volume\ of\ the\ water}\\\\\Rightarrow Volume\ of\ the\ water=\rho\times m_w = 0.997048\times 11.377=11.343426\ mL.[/tex]
The volume occupied by the unknown liquid should also be same.
Volume of unknown liquid = 11.343426 mL.
Also,
[tex]\rm m+m_l=38.028\ g\\m_l=38.028-m=38.028-17.322=20.706\ g.[/tex]
Density of the unknown liquid = [tex]\rm \dfrac{m_l}{Volume\ of\ unknown\ liquid}=\dfrac{20.706\ g}{11.343426\ mL}=1.82537\ g/mL.[/tex]
