Answer: [tex]\dfrac{1}{6}[/tex]
Step-by-step explanation:
Given : The number of students attempt to register : n = 4
Two are on the football team and two are on the basketball team.
The number of ways to select 2 students out of 4 (order doesn't matter) is given by :-
[tex]^4C_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4\times3\times2\times1}{2\times2}=6[/tex] (1)
The number of ways to select 2 students who play same sport :-
[tex]^2C_2=\dfrac{2!}{2!(2-2)!}=1[/tex] (2)
Now divide (1) by (2) we get,
The probability that both students selected play the same sport :-
[tex]=\dfrac{1}{6}[/tex]