Respuesta :

When you write the equation of a circle in the form

[tex](x-x_0)^2+(y-y_0)^2=r^2[/tex]

Then the center of the circle has coordinates [tex](x_0, y_0)[/tex] and the radius is [tex]r[/tex]

So, in your case, the center of the circle is [tex](3,7)[/tex]

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