Answer:
[tex]\frac{7}{2}[/tex]
Step-by-step explanation:
[tex]\frac{12-3y}{2} + y (\frac{2y-4}{y})[/tex]
we substitute the value of "y" in the equation:
[tex]\frac{12-3(3)}{2} + 3 (\frac{2(3)-4}{3})\\\\\frac{12-9}{2} + 3 (\frac{6-4}{3})\\\\\frac{3}{2} + 3 (\frac{2}{3})\\\\\frac{3}{2} + 2\\\\\frac{7}{2}[/tex]
