Answer:
[tex]\large\boxed{x=-\dfrac{7}{5}=-1.4}[/tex]
Step-by-step explanation:
[tex]\dfrac{1}{3}(5x+1)=-2\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}(5x+1)=(3)(-2)\\\\5x+1=-6\qquad\text{subtract 1 from both sides}\\\\5x+1-1=-6-1\\\\5x=-7\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{-7}{5}\\\\x=-\dfrac{7}{5}[/tex]
