Answer:
3
Step-by-step explanation:
Using the definition
n [tex]P_{r}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]
where n! = n(n - 1)(n - 2)........ × 3 × 2 × 1
Hence
3[tex]P_{1}[/tex]
= [tex]\frac{3!}{2!}[/tex]
= [tex]\frac{3(2)(1)}{2(1)}[/tex] = [tex]\frac{6}{2}[/tex] = 3
