[tex]\displaystyle\\d_1:~~~5x+2y=6~\implies~m_1=\boxed{-\frac{5}{2}}\\\\d_2:~~3x-ay=4~~with~~a=\frac{-12}{5}\\\\d_2:~~3x+\frac{12}{5}y=4~\implies~m_2=\frac{~-3~}{\dfrac{12}{5}}=-\frac{15}{12}=\boxed{-\frac{5}{4}}\\\\\\\bf~m_1\neq m_2\\\\\implies~~FALSE[/tex]
