Answer:
3126.9 [tex]W/m^2[/tex]
Explanation:
We are given that
Thermal conductivity of material ,k=0.16 W/mK
Thickness of hardwood board=[ptex]\Delta x[/tex]=1.5 cm =0.015 m
Temperature difference =[tex]\DeltaT=20^{\circ}[/tex]=20+273.15=293.15 k
We know that formula of heat flux
[tex]\phi=\frac{Q}{A}=\frac{k\Delta T}{\Delta x}[/tex]
[tex]\phi=\frac{293.15\times0.16}{0.015}=3126.93 W/m^2[/tex]
Hence, the heat flux passing through hardwood board=3126.9 [tex]W/m^2[/tex]
