You need to rewrite x as difference between 6x and 5x.
[tex]
3x^2+x-10=0 \\
3x^2+6x-5x-10=0 \\
3x(x+2)-5(x+2)=0 \\
(x+2)(3x-5)=0 \\
[/tex]
From here we have two solutions.
[tex]
x_1\Leftrightarrow x+2=0\Rightarrow\boxed{x_1=-2} \\
x_2\Leftrightarrow 3x-5=0\Rightarrow x_2=\boxed{\dfrac{5}{3}}
[/tex]
Hope this helps.
r3t40
