Answer:
[tex]\large\boxed{A.\ \dfrac{2^{20}}{3^8}}[/tex]
Step-by-step explanation:
[tex]\text{Use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\ \text{and}\ (a^n)^m=a^{nm}.\\\\\left(\dfrac{2^5}{3^2}\right)^4=\dfrac{(2^5)^4}{(3^2)^4}=\dfrac{2^{(5)(4)}}{3^{(2)(4)}}=\dfrac{2^{20}}{3^8}[/tex]
