Answer:
0 if the function is [tex]F(x)=\frac{4-x^2}{4-x}[/tex]. Please tell me if this is not the right function.
Step-by-step explanation:
I'm assuming the function is [tex]F(x)=\frac{4-x^2}{4-x}[/tex]. Please tell me if it is not the right assumption.
F(-2) means to use the expression called F and replace x with -2.
Like this:
[tex]F(-2)=\frac{4-(-2)^2}{4-(-2)}=\frac{4-4}{4+2}=\frac{0}{6}=0[/tex]
So the value of F(-2) is 0.
F(-2)=0.
