Answer:14
Step-by-step explanation:
A nickel is 5 cents (20% of dollar)
and a quarter is 25 cents (25% of dollar)
We have given a pile of 42 coins worth of $4.90
Let x be the no nickels and
y be the no of quarter
therefore
x+y=42 -----1
[tex]\frac{x}{4}[/tex]+[tex]\frac{y}{20}[/tex]=4.90 ---2
Solving [tex]\left ( 1\right )&\left ( 2\right )[/tex] we get
x=14 & y=28
Therefore no of nickels is 14 & no of quarters is 28
