Answer:
Yes.
Step-by-step explanation:
If a graph G doesn't have a circuit, we must have that
[tex]|E(G)|=|V(G)|-1[/tex]
where [tex]|E(G)|[/tex] is the number of edges of the graph and [tex]|V(G)|[/tex] the number of vertices. However, in this case it holds that
[tex]|E(G)|=72>68=|V(G)|.[/tex]
