Answer:
Proofs
Step-by-step explanation:
[tex]f(x) = x + \frac{3}{2} [/tex]
[tex]y = x + \frac{3}{2} [/tex]
[tex]x = y + \frac{3}{2} [/tex]
[tex]x - \frac{3}{2} = y[/tex]
[tex]{f}^{ - 1} (x) = x - \frac{3}{2} [/tex]
They are not inverse because f^-1(x) = x - 3/2 is not the inverse to g(x) = 2x - 3.
