Respuesta :

sqdancefan

Answer:

  d)  0

Step-by-step explanation:

The function is defined for x=-3, so it can simply be evaluated there.

[tex]\displaystyle\lim_{x \to -3}\left(\frac{x^2-9}{x^3+3}\right)=\frac{(-3)^2-9}{(-3)^3+3}=\frac{9-9}{-27+3}=0[/tex]

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