larrythelobsterfroms larrythelobsterfroms

20-06-2019
Mathematics

contestada

What is the perimeter, P, of a rectangle that has a length of x + 8 and a width of y − 1?

P = 2x + 2y + 18

P = 2x + 2y + 14

P = x + y − 9

P = x + y + 7

Respuesta :

Аноним Аноним

24-06-2019

Answer:

P = 2x + 2y + 14

Step-by-step explanation:

Length (L) = x + 8 units

Width (W) = y - 1 units

Perimeter (P) = 2L + 2W

P = 2(x + 8) + 2(y - 1)

P = 2x + 16 + 2y - 2

P = 2x + 2y + 16 - 2

P = 2x +2y + 14

Answer Link

LacyKuehl LacyKuehl

21-02-2020

Answer:

P = 2x + 2y + 14

Step-by-step explanation:

Answer Link

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