Answer:
Hence, the asymptotes of f(x) located at x=6 and x=-4.
Step-by-step explanation:
Since we have given that
f(x)= \frac{7}{x^2-2x-24}
We need to find the asymptotes for the above function:
Asymptotes occur when denominator becomes zero.
x^2-2x-24=0\\\\x^2-6x+4x-24=0\\\\x(x-6)+4(x-6)=0\\\\(x-6)(x+4)=0\\\\x=6,-4
