Answer:
[tex]g^{-1}[/tex](30) = 4
Step-by-step explanation:
g(x) = 8x -2
Let g(x) = y
y = 8x -2 (note: y is the range and x is the domain, we need to rearrange to make x the range and y the domain instead)
y + 2 = 8x
x = (1/8) (y + 2)
hence the inverse of g(x) is [tex]g^{-1}[/tex](y) = (1/8) (y + 2)
[tex]g^{-1}[/tex](30) = (1/8) (30 + 2) = 4
