Answer:one solution
Step-by-step explanation:
Given
a=42
b=34
angle A=117
using sine rule
[tex]\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}[/tex]
[tex]\frac{42}{sin117}=\frac{34}{sinB}[/tex]
[tex]sinB=\frac{34}{42}\times sin(117)[/tex]
sinB=0.7212
[tex]B=46.161 ^{\circ}[/tex]
and A+B+C=180
[tex]C=16.839^{\circ}[/tex]
Thus 2 triangles can be formed with given value
