Answer:
[tex]\frac{g(x)}{h(x)} =\frac{4}{(x-2)}[/tex]
Step-by-step explanation:
[tex]g(x)=4x+4\\h(x)=x^2-x-2[/tex]
First we can setup the equation as indicated
[tex]\frac{g(x)}{h(x)} =\frac{4x+4}{x^2-x-2}[/tex]
In order to simplify this, we must factor both the numerator and denominator
[tex]\frac{g(x)}{h(x)} =\frac{4(x+1)}{(x+1)(x-2)}[/tex]
The pair of (x+1)'s can cancel out and we are left with
[tex]\frac{g(x)}{h(x)} =\frac{4}{(x-2)}[/tex]
