Answer:
x = -1 or x = 6
Step-by-step explanation:
[tex]x^2-5x-6==\\\\x^2+x-6x-6=0\\\\x(x+1)-6(x+1)=0\\\\(x+1)(x-6)=0\iff x+1=0\ \vee\ x-6=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\\boxed{x=-1}\\\\x-6=0\qquad\text{add 6 to both sides}\\\boxed{x=6}[/tex]
