Answer:
60 W
Explanation:
The work done in lifting the object is given by:
[tex]W=Fd[/tex]
where
F = 30.0 N is the weight of the object
d = 10.0 m is the displacement covered by the object
Using the formula,
[tex]W=(30.0 N)(10.0 m)=300 J[/tex]
Now we can calculate the power, which is given by
[tex]P=\frac{W}{t}[/tex]
where
W = 300 J is the work done
t = 5.00 s is the time interval
Substituting,
[tex]P=\frac{300 J}{5 s}=60 W[/tex]
