Answer:
237.2 mL.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
(XMV) acid = (XMV) base.
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
(XMV) HCl = (XMV) NaOH.
For HCl; X = 1, M = 0.5 M, V = ??? mL.
For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.
∴ V of HCl = (XMV) NaOH / (XV) HCl = (1)(1.54 M)(77.0 mL) / (1)(0.5 M) = 237.2 mL.
