Respuesta :

LammettHash

By substitution,

[tex]g(2)=6.1g(1)[/tex]

[tex]g(3)=6.1g(2)=6.1^2g(1)[/tex]

[tex]g(4)=6.1g(3)=6.1^3g(1)[/tex]

and so on, so that

[tex]g(n)=6.1^{n-1}g(1)=2.7\cdot6.1^{n-1}

meandmycousinmagic

Answer:

2.7(6.1)^(n-1)

Step-by-step explanation:

[(6.1)^(n-1)]*g(1)

=[(6.1)^(n-1)]*2.7

=2.7*(6.1)^(n-1)

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