Answer:
C: [tex]x=-3[/tex] or [tex]x=4[/tex]
Step-by-step explanation:
To solve the equation [tex]x^2-x-12=0[/tex] we need to factor it
We are looking for two numbers that when multiplied give -12 and when added give -x
This means that when factored, the equation would be [tex](x-4)(x+3)=0[/tex]
Now we can set each of these equal to 0, which means that at
[tex]x=-3[/tex] and [tex]x=4[/tex] , the equation will equal 0
