Answer:
The current in a resistor decreases by a factor of 4.
Explanation:
I = [tex]\frac{E}{R}[/tex]
Where (I) is the current, (E) is the voltage and (R) is the resistance.
Decreasing the voltage by 4 gives;
I = 0.25[tex]\frac{E}{R}[/tex]
Since you have multiplied [tex]\frac{E}{R}[/tex] by 0.25,
You have to multiply I by 0.25 so the current decreases by a factor of 4.
