Answer:
= 116 g AgCl
Explanation:
CaCl2 + 2AgNO3 = Ca(NO3)2 + 2AgCl
Mass of AgCl;
1 Mole of CaCl2 = 111 g
Moles of CaCl2;
= 45 g CaCl2 (1 mol CaCl2/111 g CaCl2)
= 0.405 moles
Mole Ratio = 2: 1
Therefore; moles ,of AgCl
= 0.405 moles × 2
= 0.810 moles
Thus;
Mass of AgCl = 0.810 moles × 143.5 g AgCl
= 116 g AgCl
