Respuesta :

sbcardinals

Answer:

4j^3 + 5j^2 + 7j - 1

Step-by-step explanation:

(8j^3 - 3j^2 + 5)-(4j^3+8j^2+7j-6)​

Distribute the -1 in front of the (4j^3+8j^2+7j-6)​

8j^3 - 3j^2 + 5 - 4j^3 + 8j^2 + 7j - 6

We can combine anything with the same exponent number that "j" is raised to

8j^3 - 4j^3 = 4j^3

-3j^2 + 8j^2 = 5j^2

7j is just 7j since there is nothing else with just j in it

5 - 6 = -1

Add these together

4j^3 + 5j^2 + 7j - 1 is our final answer

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