Answer:
[tex]\frac{108x^8}{y^5}[/tex]
Step-by-step explanation:
[tex](\frac{3x^2}{y} )^3 * (\frac{2x}{y})^2=\frac{3^3x^6}{y^3} *\frac{2^2x^2}{y^2} =\\= \frac{108x^8}{y^5}[/tex]
