Answer:
[tex]\large\boxed{y-2=-2(x+3)}[/tex]
Step-by-step explanation:
The point-slop form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-3, 2) and (-7, 10). Substitute:
[tex]m=\dfrac{10-2}{-7-(-3)}=\dfrac{8}{-4}=-2\\\\y-2=-2(x-(-3))\\\\y-2=-2(x+3)[/tex]
