Answer:
[tex]\large\boxed{\sin C=\dfrac{5}{13}}[/tex]
Step-by-step explanation:
[tex]sin=\dfrac{opposite}{hypotenuse}\to\sin C=\dfrac{AB}{AC}\\\\\text{We have}\ AB=25,\ AC=65.\ \text{Substitute:}\\\\\sin C=\dfrac{25}{65}=\dfrac{25:5}{65:5}=\dfrac{5}{13}[/tex]
