Answer:
[tex]\boxed{t=15}[/tex]
Step-by-step explanation:
Function: [tex]f(t)=2^{t/3}[/tex]
You need to replace f(t) for 32 and isolate "t", like this:
[tex]f(t)=2^{t/3}\\ 32=2^{t/3}\\ 2^5=2^{t/3}[/tex]
Since both bases are 2, we only take the powers:
[tex]5=\dfrac{t}{3}\;\Longrightarrow 5\cdot3=t=15[/tex]
