Answer:
[tex]\large\boxed{(x-3)^2+(y-7)^2=36}[/tex]
Step-by-step explanation:
The equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have
(3, 7) - center
r = 6 - radius
Substitute:
[tex](x-3)^2+(y-7)^2=6^2\\\\(x-3)^2+(y-7)^2=36[/tex]
