lilolexi
lilolexi
19-09-2014
Mathematics
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How do you do [tex] x^{2} -9x=15[/tex]
Respuesta :
Аноним
Аноним
19-09-2014
[tex]x^2-9x=15\\x^2-9x-15=0\\a=1;\ b=-9;\ c=-15\\\Delta=b^2-4ac\to\Delta=(-9)^2-4(1)(-15)=81+60=141\\\\x=\frac{-b\pm\sqrt\Delta}{2a}\to x=\frac{9\pm\sqrt{141}}{2}[/tex]
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