Answer:
The approximate volume of the remaining solid is [tex]140.64\ in^{3}[/tex]
Step-by-step explanation:
we know that
The approximate volume is equal to the volume of the cube minus the volume of the cylinder
so
[tex]V=b^{3}-\pi r^{2}h[/tex]
we have
[tex]b=6\ in[/tex]
[tex]r=4/2=2\ in[/tex] -----> the radius is half the diameter
[tex]h=6\ in[/tex]
substitute the values
[tex]V=6^{3}-(3.14)(2^{2})(6)=140.64\ in^{3}[/tex]
