Answer:
[tex]\large\boxed{D.\ x=-2(y+3)^2-1}[/tex]
Step-by-step explanation:
The equation of a horizontal parabola in the standard form:
[tex]x=a(y-k)^2+h[/tex]
(h, k) - vertex
if a > 0, then open right
if a < 0, then open left
We have the vertrex (-1, -3) and the parabola is open left (a < 0).
Therefore the equation of a given parabola could be:
[tex]x=-2(y-(-3))^2+(-1)=-2(y+3)^2-1[/tex]
