Answer:
see explanation
Step-by-step explanation:
Equate the quadratic to zero
x² - 5x + 4 = 0 ← in standard form
with a = 1, b = - 5, c = 4
Using the quadratic formula to solve for x
x = ( -(- 5) ± [tex]\sqrt{(-5)^2-(4(1)(4)}[/tex] ) / 2
= ( 5 ± [tex]\sqrt{9}[/tex] ) / 2
= ( 5 ± 3 ) / 2
x = [tex]\frac{5-3}{2}[/tex] or x = [tex]\frac{5+3}{2}[/tex], hence
x = 1 or x = 4
The solutions are real, rational and distinct
