Answer : The correct option is, [tex]10^{-4}M[/tex]
Explanation : Given,
pH = 10
First we have to calculate the pOH.
[tex]pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-10=4[/tex]
Now we have to calculate the [tex]OH^-[/tex] concentration.
[tex]pOH=-\log [OH^-][/tex]
[tex]4=-\log [OH^-][/tex]
[tex][OH^-]=1.0\times 10^{-4}M[/tex]
Therefore, the [tex]OH^-[/tex] concentration is, [tex]1.0\times 10^{-4}M[/tex]
