Respuesta :

Ashraf82

Answer:

The answer is (c) ⇒ e = 3 and k = 1/2 , conic: hyperbola

Step-by-step explanation:

∵ r = ek/(1 ± ecosФ)

∵ r = 3/(2 - 6cosФ) ⇒ ÷ 2 up and down

∴ r = (3/2)/(1 - 3cosФ)

∴ e = 3

∵ ek = 3/2 ⇒ 3k = 3/2

∴ k = 1/2

∵ e > 1

∴ The conic is hyperbola

Answer:

the answer is C

Step-by-step explanation:

i did the assignment on edg

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