Answer:
[tex]\large\boxed{x\approx1.45}[/tex]
Step-by-step explanation:
[tex]4e^x=17\qquad\text{divide both sides by 4}\\\\e^x=\dfrac{17}{4}\qquad \ln\ \text{of both sides}\\\\\ln e^x=\ln\dfrac{17}{4}\qquad\text{use}\ \log_aa^n=n\\\\x=\ln\dfrac{17}{4}\\\\x\approx1.45[/tex]
