Answer:
[tex]\large\boxed{d.\ -\dfrac{11}{2}}[/tex]
Step-by-step explanation:
[tex]11x^{-3}y^{-1}\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=11\left(\dfrac{1}{x^3}\right)\left(\dfrac{1}{y}\right)=\dfrac{11}{x^3y}\\\\\text{Substitute the values of}\ x\ \text{and}\ y:\\\\x=-1,\ y=2\\\\\dfrac{11}{(-1)^3(2)}=\dfrac{11}{(-1)(2)}=\dfrac{11}{-2}=-\dfrac{11}{2}[/tex]
